tag:blogger.com,1999:blog-7629869410369132909.post8007329172050578311..comments2020-05-10T19:50:57.213-07:00Comments on THE INDIAN MATHEMATICIAN, NBHM CSIR GATE EXAM PREVIOUS YEAR QUESTIONS SOLUTION THROUGH CONCEPTS: NBHM 2020 PART C Question 27 Solution (Structure of the group $\frac{\Bbb Q}{n \Bbb Z}$)THE INDIAN MATHEMATICIANhttp://www.blogger.com/profile/10264936586823809199noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-7629869410369132909.post-2214144388849739822020-05-10T19:50:57.213-07:002020-05-10T19:50:57.213-07:00There is no condition on p but due to condition on...There is no condition on p but due to condition on q as it divides m it must be less than or equal to m and p is also an integer ,which is also must be less than m bcz in Z+p/q if p/q >1 then p/q=1+r/q that imply Z+p/q =Z+r/q ,there no of elements in Hm become finite Anonymoushttps://www.blogger.com/profile/00442342784788507508noreply@blogger.comtag:blogger.com,1999:blog-7629869410369132909.post-68621796525890530332020-05-10T12:35:01.349-07:002020-05-10T12:35:01.349-07:00There is no condition on $p$. Therefore $H(m)$ is ...There is no condition on $p$. Therefore $H(m)$ is infinite. is it fine now?THE INDIAN MATHEMATICIANhttps://www.blogger.com/profile/10264936586823809199noreply@blogger.comtag:blogger.com,1999:blog-7629869410369132909.post-16222493848709988612020-04-30T22:52:36.031-07:002020-04-30T22:52:36.031-07:00How H(m) is infinite, can't understandHow H(m) is infinite, can't understandAnonymoushttps://www.blogger.com/profile/00442342784788507508noreply@blogger.comtag:blogger.com,1999:blog-7629869410369132909.post-264028533586383742020-04-30T11:33:49.446-07:002020-04-30T11:33:49.446-07:00Can u plz elaborate H(m) in option 3Can u plz elaborate H(m) in option 3Anonymoushttps://www.blogger.com/profile/00442342784788507508noreply@blogger.com